Drop Stop Reasoning
1. In the container, gravity is a downward force and the normal force is an upwards force on the water.
2. The water is squished between these forces making an outwards force, forcing water out the hole.
3. The water stopped leaving the container when dropped, so forces must have become balanced.
4. The force of gravity on the water: Fw = M x g
5. The force of acceleration on the water: Fa = M x a
6. The m is the same for both g = a
7. The Fw + (-Fa) = 0 so the forces are balance.
8. This proves the normal force becomes zero.
Drop Stop Reasoning
1. In the container, gravity is a downward force and the normal force is an upwards force on the water.
2. The water is squished between these forces making an outwards force, forcing water out the hole.
3. The water stopped leaving the container when dropped, so forces must have become balanced.
4. The force of gravity on the water: Fw = M x g
5. The force of acceleration on the water: Fa = M x a
6. The m is the same for both g = a
7. The Fw + (-Fa) = 0 so the forces are balance.
8. This proves the normal force becomes zero.
Drop Stop Reasoning
1. In the container, gravity is a downward force and the normal force is an upwards force on the water.
2. The water is squished between these forces making an outwards force, forcing water out the hole.
3. The water stopped leaving the container when dropped, so forces must have become balanced.
4. The force of gravity on the water: Fw = M x g
5. The force of acceleration on the water: Fa = M x a
6. The m is the same for both g = a
7. The Fw + (-Fa) = 0 so the forces are balance.
8. This proves the normal force becomes zero.
Drop Stop Reasoning
1. In the container, gravity is a downward force and the normal force is an upwards force on the water.
2. The water is squished between these forces making an outwards force, forcing water out the hole.
3. The water stopped leaving the container when dropped, so forces must have become balanced.
4. The force of gravity on the water: Fw = M x g
5. The force of acceleration on the water: Fa = M x a
6. The m is the same for both g = a
7. The Fw + (-Fa) = 0 so the forces are balance.
8. This proves the normal force becomes zero
1. In the container, gravity is a downward force and the normal force is an upwards force on the water.
2. The water is squished between these forces making an outwards force, forcing water out the hole.
3. The water stopped leaving the container when dropped, so forces must have become balanced.
4. The force of gravity on the water: Fw = M x g
5. The force of acceleration on the water: Fa = M x a
6. The m is the same for both g = a
7. The Fw + (-Fa) = 0 so the forces are balance.
8. This proves the normal force becomes zero.
Drop Stop Reasoning
1. In the container, gravity is a downward force and the normal force is an upwards force on the water.
2. The water is squished between these forces making an outwards force, forcing water out the hole.
3. The water stopped leaving the container when dropped, so forces must have become balanced.
4. The force of gravity on the water: Fw = M x g
5. The force of acceleration on the water: Fa = M x a
6. The m is the same for both g = a
7. The Fw + (-Fa) = 0 so the forces are balance.
8. This proves the normal force becomes zero.
Drop Stop Reasoning
1. In the container, gravity is a downward force and the normal force is an upwards force on the water.
2. The water is squished between these forces making an outwards force, forcing water out the hole.
3. The water stopped leaving the container when dropped, so forces must have become balanced.
4. The force of gravity on the water: Fw = M x g
5. The force of acceleration on the water: Fa = M x a
6. The m is the same for both g = a
7. The Fw + (-Fa) = 0 so the forces are balance.
8. This proves the normal force becomes zero.
Drop Stop Reasoning
1. In the container, gravity is a downward force and the normal force is an upwards force on the water.
2. The water is squished between these forces making an outwards force, forcing water out the hole.
3. The water stopped leaving the container when dropped, so forces must have become balanced.
4. The force of gravity on the water: Fw = M x g
5. The force of acceleration on the water: Fa = M x a
6. The m is the same for both g = a
7. The Fw + (-Fa) = 0 so the forces are balance.
8. This proves the normal force becomes zero